No, there are 27 combinations(when you still account for the fact that you can have three windows machines).
You can see it in that way:
machine1: L, machine2: W, machine3: O
machine1: L, machine2: W, machine3: W
The reason why it matters is that you have more ways to have exactly two linux machines:
m1: L, m2: L, m3: O
m1: L, m2: O, m2: L,
etc.
That gives you 2*3 ways of having exactly two linux machines (you have 3 ways of having exactly one non linux machine, and then this machine can be two different things). If you say that LLO is OLL, you would have only 2 ways of having exactly two linux machines.
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No, there are 27 combinations(when you still account for the fact that you can have three windows machines).
You can see it in that way:
machine1: L, machine2: W, machine3: O machine1: L, machine2: W, machine3: W
The reason why it matters is that you have more ways to have exactly two linux machines:
m1: L, m2: L, m3: O
m1: L, m2: O, m2: L,
etc.
That gives you 2*3 ways of having exactly two linux machines (you have 3 ways of having exactly one non linux machine, and then this machine can be two different things). If you say that LLO is OLL, you would have only 2 ways of having exactly two linux machines.
Hope this makes sense.
I see. LLO and LOL are different occurences and must be counted for. Thanks for clarifying!