Skip to content

Comment on A gentle introduction to statistical relational learningparent

Comments

Partition functions are usually hard to compute as they require a sum or integral over the entire parameter space. In this case, it's "Z is a normalizing constant, that is: it's the sum of the values of all possible assignments."

So perhaps sum_x { exp( sum_i { w[i] * g[i](x) } ) }

AboutSource Built by g1lg1l

Hackerly is an independent reader for Hacker News, built on the public HN API. Not affiliated with Y Combinator.