Comment on A gentle introduction to statistical relational learningparentComments−tel11yPartition functions are usually hard to compute as they require a sum or integral over the entire parameter space. In this case, it's "Z is a normalizing constant, that is: it's the sum of the values of all possible assignments."So perhaps sum_x { exp( sum_i { w[i] * g[i](x) } ) }
Comments
Partition functions are usually hard to compute as they require a sum or integral over the entire parameter space. In this case, it's "Z is a normalizing constant, that is: it's the sum of the values of all possible assignments."
So perhaps sum_x { exp( sum_i { w[i] * g[i](x) } ) }