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Comment on Show HN: Frugon – Find which LLM calls a cheaper model could handle (local, MIT)parent

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As well. Someday costed opcodes and sharded redundancy for all of this;

No search needed because the problem is discrete and small.

If an algorithm selects according to rank, there's a cost/score/fitness/survival/error function (that assumes or imposes a distance metric to make a metric space).

Awhile back I had to match exterior paint to printed paint swatches and I'm stereotypically not good at colors, so finally I arrived at just A/B; this one or this one and discard.

As well. Someday costed opcodes and sharded redundancy for all of this;

Hmm, noted.

If an algorithm selects according to rank, there's a cost/score/fitness/survival/error function.

- Yes, what I'm saying is that frugon has a small enough candidate pool that it can all be evaluated at the same time. It doesn't need to search through it.

Awhile back I had to match exterior paint to printed paint swatches and I'm stereotypically not good at colors, so finally I arrived at just A/B; this one or this one and discard.

- This is exactly the shape the judge prompt takes in frugon.

See: src/frugon/measure.py

Then search: JUDGE_PROMPT_TEMPLATE

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