Comment on Fast Inverse Square RootComments−FredBrach13ywhy?Also because x * 1/sqrt(x) == sqrt(x) (so on a pentium, an sqrt was 3 cycles further an inv-sqrt, pretty cheap for an sqrt)
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why?
Also because x * 1/sqrt(x) == sqrt(x) (so on a pentium, an sqrt was 3 cycles further an inv-sqrt, pretty cheap for an sqrt)