Comment on Harvard chemist talks about the problem of solving problemsparentComments−001sky14yThis is an interesting thesis, but not self evidently true.This is your logic:A is independent of B.B could be anything.A is independent of B._______But...B could be a Set such that A is a subset of B.A and B could also be terms in a Set Z, which includes A & B
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This is an interesting thesis, but not self evidently true.
This is your logic:
A is independent of B.
B could be anything.
A is independent of B.
_______
But...
B could be a Set such that A is a subset of B.
A and B could also be terms in a Set Z, which includes A & B