Comment on Security vulnerability in MySQL ubuntuparentComments−jontro14yBecause when the return value is truncated to a char, the last two bytes in the int would have to be 0x00, which is 1/256 assuming the return value is a completley random int.
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Because when the return value is truncated to a char, the last two bytes in the int would have to be 0x00, which is 1/256 assuming the return value is a completley random int.