Comment on Zero Tolerance for BiasparentComments−Jaxan2yThat is not enough because k is allowed to depend on n.−LegionMammal9782yFor n > 2, n! does not divide 2^k for any k, since n! has a factor of 3.
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That is not enough because k is allowed to depend on n.
For n > 2, n! does not divide 2^k for any k, since n! has a factor of 3.