Comment on Zero Tolerance for BiasparentComments−omoikane2yif you don’t have more than 230 bits of entropyShould this be 226 instead of 230, since 2**225 < 52! < 2**226 ?−mlyle2yI did round, but you probably need more than 226. Because 52! does not divide into any power of 2.Imagine if you had 5 possible hands, and 3 bits of entropy. Some hands are going to be twice as likely than others (pigeon hole principle).So if you have 4 bits more, the least common hands will be 31/32 as common as the most common hands.
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Should this be 226 instead of 230, since 2**225 < 52! < 2**226 ?
I did round, but you probably need more than 226. Because 52! does not divide into any power of 2.
Imagine if you had 5 possible hands, and 3 bits of entropy. Some hands are going to be twice as likely than others (pigeon hole principle).
So if you have 4 bits more, the least common hands will be 31/32 as common as the most common hands.