Skip to content

Comment on YX Problemparent

Comments

It might predate HN but you are looking at the XY problem, not the YX problem. In this case, they are not commutative.

It seems that the YX problem is a derivative of the XY problem. In both cases we solve for X.

seems

If you're actually unsure, then be sure. It's a derivative.

It's a play on words.

Can you explain it? I don't get it.

I mean, I see how "derivative" could be wordplay, but I don't see how "seems" is wordplay.

Yes the YX problem has a YX problem.

AboutSource Built by g1lg1l

Hackerly is an independent reader for Hacker News, built on the public HN API. Not affiliated with Y Combinator.