As in the minimum character set? As of 1.9.2, you can do lambdas with a = ->(x){do stuff} and call them with a[3]. So I think you could probably translate to SKI calculus using only: (){}->[]
Since SKI gives you lambda calculus, and the lambda calculus is turing complete, you might win that way. :)
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As in the minimum character set? As of 1.9.2, you can do lambdas with a = ->(x){do stuff} and call them with a[3]. So I think you could probably translate to SKI calculus using only: (){}->[]
Since SKI gives you lambda calculus, and the lambda calculus is turing complete, you might win that way. :)