> it assumes the quadratic case of the Fundamental Theorem of Algebra
No, it doesn't; it proves that case. The key step in the proof is the fact that, over the complex numbers, every number has a square root: from that it follows that the factorization used in the proof must always exist.
Comments
> it assumes the quadratic case of the Fundamental Theorem of Algebra
No, it doesn't; it proves that case. The key step in the proof is the fact that, over the complex numbers, every number has a square root: from that it follows that the factorization used in the proof must always exist.