Comment on Going beyond the Golden RatioparentComments−ComplexSystems7yHow do the results change if you use multiplicative error rather than additive error? That is, rather than |x-p/q|, you use max(x/(p/q), (p/q)/x). This is sometimes useful when trying to approximate rationals.−extremelearning7yGood question, but I don't know and haven't really done anything substantially related that might even give us a hint.Hopefully someone else chime in on this thread. ;)
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How do the results change if you use multiplicative error rather than additive error? That is, rather than |x-p/q|, you use max(x/(p/q), (p/q)/x). This is sometimes useful when trying to approximate rationals.
Good question, but I don't know and haven't really done anything substantially related that might even give us a hint.
Hopefully someone else chime in on this thread. ;)