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Comment on Rigging elections with integer linear programmingparent

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Well sure if you add information not in the problem (P(C|X)=0) you can get the answer you want.

It is given that P(A | X) = .99 and P(B | X) = .01, because (by assumption) the first doctor gives you perfect predictions given the information X. Clearly P(A or B | X) = 1, so P(C | X) = 0 for any C not in A or B.

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