Comment on Get any a-Z char using only []()+{}/. in JavaScript (for XSS obfuscation)parentComments−tr4nslator16yYou can even do that in half the bytes by making use of all unary operators together: -~+[] -~ is a good proxy for ++ when incrementing unassigned variables.
Comments
You can even do that in half the bytes by making use of all unary operators together:
-~ is a good proxy for ++ when incrementing unassigned variables.