But not into a register right? Given my (flawed) assumption that there would be two reads, whilst the first might load the second into the cache, it wouldn't load into a register without another instruction telling it to. This costs a lot less than the cache fetch but it still has a cost.
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But not into a register right? Given my (flawed) assumption that there would be two reads, whilst the first might load the second into the cache, it wouldn't load into a register without another instruction telling it to. This costs a lot less than the cache fetch but it still has a cost.