Is argc really a const in C++'s main? I can't imagine why it would be, given that argv++; argc--; is a very standard idiom in command-line argument processing.
Seeing I wasn't using it, I thought I might hint to the optimiser that it could optimise it away. But now that you mention it, the argv should have been const char * const
The optimizer is quite able to recognize that a variable is unused. :-)
In fact, if you compile that code with warnings turned on, you'll get a "variable is not used" warning -- which most style guides say should be silenced by adding the following line to the start of your function:
Comments
He could have put in some templating to make it easy for the next person to quit.
Is argc really a const in C++'s main? I can't imagine why it would be, given that argv++; argc--; is a very standard idiom in command-line argument processing.
Seeing I wasn't using it, I thought I might hint to the optimiser that it could optimise it away. But now that you mention it, the argv should have been const char * const
The optimizer is quite able to recognize that a variable is unused. :-)
In fact, if you compile that code with warnings turned on, you'll get a "variable is not used" warning -- which most style guides say should be silenced by adding the following line to the start of your function:
Overkill